Work Equals Voltage Times Charge

Voltage is a way of measuring e fields.

Work equals voltage times charge. Oct 24 2009 2 hamdard full member level 3. The power p in watts w is equal to the voltage v in volts v times the current i in amps a. Your question then reads. There are several equivalent ways to look at this.

If a unit of electrical charge were placed in a location the voltage indicates the potential energy of it at that point. Voltage is a representation of the electric potential energy per unit charge. The charging current stops flowing and the capacitor is said to be fully charged. That s no more than a definition of the potential energy.

The voltage across the 100uf capacitor is zero at this point and a charging current i begins to flow charging up the capacitor until the voltage across the plates is equal to the 12v supply voltage. Oct 25 2009 3 m. Constant electric field the case of a constant electric field as between charged parallel plate conductors is a good example of the relationship between work and voltage. So if we perform work by lifting a quantity of charge against an e field then the electrical energy stored is equal to the work needed to lift the charge.

Then vc vs 12v. Charge q is measured in coulombs c. Charge current x time. Electric power like mechanical power is the rate of doing work measured in watts and represented by the letter p the term wattage is used colloquially to mean electric power in watts the electric power in watts produced by an electric current i consisting of a charge of q coulombs every t seconds passing through an electric potential difference of v is.

Energy is equal to charge times voltage. Why is the amount of energy determined by multiplying the charge times the voltage simple answer. The voltage v in volts v is equal to the square root of the power p in watts w times the resistance r in ohms ω. The power p in watts w is equal to the squared voltage v in volts v divided by the resistance r in ohms ω.

One is to say that for any conservative force mathbf f one can define the potential energy ep as an associated potential field such as mathbf f frac partial ep partial r or maybe more formally mathbf f nabla ep. Thus 1 6kj of work is required to drive 16c from point a to point b. Electrical current is the rate of flow of charge in a circuit. The electric field is by definition the force per unit charge so that multiplying the field times the plate separation gives the work per unit charge which is by definition the change in voltage.

E q x v can someone show me why. Joined jun 9 2006 messages 177 helped 17 reputation 38 reaction score 9 trophy points 1 298 activity points 2 354 re. This means that it would take 1 6kj of work to drive a positive charge of 16c from point b to point a. In other words it is a measurement of the energy contained within an electric field or an electric circuit at a given point it is equal to the work that would have to be done per unit charge.

Each electron carries a tiny amount of charge 1 6 x 10 19 coulombs.