Current Amps Formula
Secondary current in amps i s a s kva 1000 v s v example.
Current amps formula. When a voltage v and resistance are given then you ought to use a formula for current. From this post learn complete about how to calculate the load current of 3 phase motor. Amps watts pf. The si unit of voltage is a volt the unit of amperage is an ampere usually shortened to amp and the unit of power is a watt.
Then the formula will be. So to calculate watts the following formula is used. Amp watt volt. Current i voltage v resistance r i amps v volts r ω for example.
How to calculate watts. A current of 2 amps can be written as 2a. What is the current in amps when the power consumption is 330 watts and the voltage supply is 110 volts. This is represented by.
Full load current in amps 25 1000 230 108 696 a. The current i in amps a is equal to the square root of the power p in watts w divided by the resistance r in ohms ω. If you want to calculate secondary current then we need to take secondary voltage only. The 3 phase load current amps formula is explain with a three phase load voltage induction motor nameplate data.
This post about the 3 phase motor current calculation formula explanation. Calculate the full load current of the single phase transformer rating of 25kva 230 volts. Your single phase current will be represented by i and measured in amps a and can be calculated by dividing the real power p measured in watts w divided by a power factor pf multiplied by the root mean square rms voltage as measured in volts v. The phase current i in amps a is equal to the real power p in watts w divided by the power factor pf times the rms.
You can calculate current using the given formula. Find the current flowing through a 3 ω resistor when a potential difference of 30 v is applied. The convention of using watts amps and volts. I a p w pf x v v or more simply.
The voltage v in volts v is equal to the current i in amps a times the resistance r in ohms ω. A w v. Ac single phase watts to amps calculation formula. W v i.
Resistance r voltage v and amperage i electric current can also be a source of power p so that it can release or transport some energy. When talking about the fundamental ohm s law we consider a few physical quantities. The bigger the current the more electricity is flowing.